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    DWG.ruProjet:

    Site: Fait par: CpLDate: 2010-12-02Verif. par:Classement

    Dfinition

    SINGLE ANGLE

    moment capacity calculation(Chapter F of ANSI/AISC 360-05)

    Mu 3.81kN m:= - resultant flexural moment due to factored loads

    Fy 300MPa:= 0.9:=

    Angle L102*102*7.9

    b 4in 101.6 mm=:=

    t5

    16in 7.94 mm=:=

    y' 1.11in 28.19 mm=:=

    Sc 1.27in3

    20.81 103

    mm3

    =:=- elastic section modulus from dimentions and properties table

    1.Yelding

    Sw 1.27in3

    := - elastic section modulus to the leg tip about the major principal axis

    My1 Fy Sw 6.24 kN m=:= - yield moment about geometrical axis

    Mn1 1.5My1 9.37 kN m=:= - nominal flexural strength

    2.Lateral-Torsional Buckling

    Lateral-torsional buckling modification factor calculation:

    Mmax Mu 3.81 kN m=:= - absolute value of maximum moment in the unbraced segment

    Ma 2850N m:= - absolute value of moment at quarter point of the unbraced segment

    Mb 3810N m:= - absolute value of moment at centerline of the unbraced segment

    Mc 2850N m:= - absolute value of moment at three-quarter point of the unbraced segment

    - for singly symmetric members subjected to single curvaturebending (for other

    see page 16.1-46 ANSI/AISC 360-05)Rm 1.0:=

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    DWG.ruProjet:

    Site: Fait par: CpLDate: 2010-12-02Verif. par:Classement

    Cb

    12.5Mmax

    2.5 Mmax 3 Ma+ 4 Mb+ 3Mc+Rm

    12.5Mmax

    2.5 Mmax 3 Ma+ 4 Mb+ 3Mc+Rm

    1.5if

    1.14=:=

    Elastic lateral-torsional buckling moment calculation:

    Le 3040mm:= - laterally unbraced lengthof a member

    a1 :=ATTENTION: To choose - the bending is about one of the geometric axesof an equal-leg angle with lateral-torsional restraint at the

    point of maximum moment (NO or YES):

    ke 1 a1 1=if

    1.25 a1 2=if

    1=:=

    ky 0.8 a1 1=if

    1 a1 2=if

    0.8=:=

    a2 :=

    ATTENTION: To choose - type of the stress at the toe (COMPRESSIONor TESION):

    Me ke

    0.66 E b4

    t Cb

    Le2

    1 0.78Le t

    b2

    2

    + 1

    a2 3=if

    ke

    0.66 E b4

    t Cb

    Le2

    1 0.78Le t

    b2

    2

    + 1+

    a2 4=if

    :=

    Me 45.27 kN m=

    My2 My1 ky 4.99 kN m=:=

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    DWG.ruProjet:

    Site: Fait par: CpLDate: 2010-12-02Verif. par:Classement

    Mn2 0.920.17Me

    My2

    Me Me My2if

    1.92 1.17My2

    Me

    My2 Me My2> 1.92 1.17

    My2

    Me

    My2 1.5My2if

    1.5My2( ) 1.92 1.17My2

    Me

    My2 1.5My2>if

    7.49 kN m=:=

    3.Leg Local Buckling

    Width_Thickness_Ratio "Compact"b

    t0.54

    E

    Fy

    if

    "Noncompact" 0.54 EFy

    bt

    < 0.91 EFy

    if

    "Slender" 0.91E

    Fy

    b

    t