CLASE 10
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Transcript of CLASE 10
![Page 1: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/1.jpg)
CLASE 10
![Page 2: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/2.jpg)
![Page 3: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/3.jpg)
Racionaliza los denominadores:
a) 53
b) 22 4+5
53
= 33
.
= 22 4+5
4–5 4–5. =
22(4–5)
(4) –(5)2 2
16–5
22(4–5) =
22(4–5) =
11=2(4–5)
=53 3
= 53 (3)2
.Expresiones conjugadas
![Page 4: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/4.jpg)
3 + 4i 3 – 4i
CONJUGADOSa+bi a–bi
–7+2i –7–2i0,8–4i2 0,8+4i2
3–4i . (3) –(4i )=2 2
3+4i 2= 9–16i
= 9 +16 = 25 +
producto.
.
.+
Números complejos
= 9–16(–1)
.
![Page 5: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/5.jpg)
Efectúa:
5+4i –2
.
5 4i= +–2 –2
=52 2i
![Page 6: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/6.jpg)
Efectúa: 2–i–1–2i
= 2–i–1–2i
–1+2i–1+2i
.
(–1) –(2i )2 2=–2+4i+i –2i
2
1 – (2
i )
2 2= –2 + 5i + 2
5i1 – 4i 2
=1 + 4
5i= 5i=5 = i
–1
–1
.
![Page 7: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/7.jpg)
En la práctica, para dividir dos números complejos
en forma binómica procedemos a multiplicar el dividendo y el divisor
por el número conjugado del divisor.
![Page 8: CLASE 10](https://reader036.fdocuments.co/reader036/viewer/2022082819/56813832550346895d9fe04e/html5/thumbnails/8.jpg)
Calcula:
ESTUDIO INDIVIDUAL
.
3 – i 1 – i 3
3 – i2
i
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2–i–1–2i
2Efectúa:
= 1= i
.
( )2
(–1–2i )2
(2–i )2= = 4 – 4i + i 2
(–1–2i )2 –(1+2i )2
= =1 + 4i + 4i2
1 + 4i + 4i 2=4–4i –1
1+4i –4
= 3–4i –3+4i
·–3–4i –3–4i
=9 +16
(–3)2–(4i)2
(3–4i ) (–1) (3+4i )
= 9–16i 2 =25
(–1) (9 +16) = –1
–1