Práctica No 3 Tarea.doc

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Determine mediante suma parciales la serie de las siguientes sucesiones utilizando como dominio los cuatro primeros números naturales. a) a 1 = (-1) 1-1 .2 1 = 2 a 2 = (-1) 2-1 .2 2 =-4 a 3 = (-1) 3-1 .2 3 = 8 a 4 =(-1) 4-1 .2 4 = -16 S1=2 S2=s1+-4=-2 S3=s2+8=6 S4=s3+-16=-10 b) a 1 = 1 + 2 =3/1=3 2(1)-1 a 2 = 2 + 2 =4/3 2(2)-1 a 3 = 3 + 2 =5/5=1 2(3)-1 a 4 = 4 + 2 =6/7 2(4)-1 S1=3 S2=s1+4/3=13/3 S3=s2+1=16/3 S4=s3+6/7=130/21

Transcript of Práctica No 3 Tarea.doc

Page 1: Práctica No 3  Tarea.doc

Determine mediante suma parciales la serie de las siguientes sucesiones utilizando como dominio los cuatro primeros números naturales.

a)

a1= (-1)1 - 1.21= 2 a2= (-1)2 - 1.22=-4 a3= (-1)3 - 1.23= 8 a4=(-1)4 - 1.24= -16

S1=2S2=s1+-4=-2S3=s2+8=6S4=s3+-16=-10

b)

a1= 1 + 2 =3/1=3 2(1)-1 a2= 2 + 2 =4/3 2(2)-1 a3= 3 + 2 =5/5=1 2(3)-1 a4= 4 + 2 =6/7 2(4)-1S1=3S2=s1+4/3=13/3S3=s2+1=16/3S4=s3+6/7=130/21

c) an= n+2

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n a1= 1+2 =3 1 a2= 2+2 =2 2 a3= 3+2 =5/3 3 a4= 4+2 =6/4=3/2 4

S1=3S2=s1+2=5S3=s2+5/3=20/3S4=s3+3/2=49/6

d) an = 2n-2_____ n(n+2)(n+1

a1 = 2(1)-2_____ = 0 1(1+2)(1+1) a2 = 2(2)-2_____ = 1/12 2(2+2)(2+1) a3 = 2(3)-2_____ = 1/5 3(3+2)(3+1) a4 = 2(4)-2_____ = 1/20 4(4+2)(4+1)

S1=0S2=s1+1/12=1/12S3=s2+1/5=17/60S4=s3+1/20=1/3

e) an =5n(n+1)(n-3)

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a1 = 5(1)(1+1)(1-3)=-20 a2 = 5(2)(2+1)(2-3)=-30 a3 = 5(3)(3+1)(3-3)=0 a4 = 5(4)(4+1)(4-3)=100

S1=-20S2=s1+-30=-50S3=s2+0=-50S4=s3+100=50

f) an= __ 3n+2___ 2n(n+2)(n+1

a1= _ 3(1)+2___ =6/12 2(1)(1+2)(1+1) a2= 3(2)+2___ =8/48 2(2)(2+2)(2+1) a3= _ 3(3)+2___ =11/120 2(3)(3+2)(3+1) a3= _ 3(4)+2___ =14/240 2(4)(4+2)(4+1)

S1=-6/12S2=s1+8/48=2/3S3=s2+11/120=91/120S4=s3+14/240=49/60