predimensionamiento de columnas
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Transcript of predimensionamiento de columnas
Diseñar una columna cuadrada sujeta a carga axial pura
= 150 Tf'c = 210
= 4200
Solucion:
1.- Dimensionamiento
≥ 1500000.45 (210 + 0.02 x 4200)
= 1133.79
AdoptamosS = 35 cmT = 35 cm
= 1225
2.- Refuerzo Longitudinal
150000 = 0.8 [0.85 x 210 (1225 - As) + 4200 x As]0.7
= 12.23
= 0.01 x 1225
= 12.25
= 12.25
Usar : 4 ø N° 5 + 4 ø N° 4
As = 13.00
N° 5
N° 4 0.35 m
Pu
Kg/cm2
fy Kg/cm2
Ag
Ag cm2
Ag cm2
As cm2
Asmin
Asmin cm2
As cm2
cm2
𝑨_𝒈≥𝑷𝒖/(𝟎.𝟒𝟓(〖 ′〗𝒇 _𝒄+ 𝝆 . 𝒇_𝒚))
𝑷_𝒏=𝟎.𝟖𝟎 [𝟎.𝟖𝟓∙ 〖 ′〗𝒇 _𝒄 (𝑨_𝒈−𝑨_𝒔 )+𝒇_𝒚∙ _𝑨 𝒔 ]
𝑨_(𝒔 𝒎𝒊𝒏)=𝟎.𝟎𝟏 𝒙 𝑨_𝒈
0.35 m
Diseñar una columna cuadrada sujeta a carga axial pura
= 150 Tf'c = 1000
= 4200
Solucion:
1.- Dimensionamiento
≥ 1500000.45 (1000 + 0.02 x 4200)
= 307.50
AdoptamosS = 25 cmT = 25 cm
= 625
2.- Refuerzo Longitudinal
150000 = 0.8 [0.85 x 1000 (625 - As) + 4200 x As]0.7
= -78.62
= 0.01 x 625
= 6.25
= 6.25
Usar : 2 ø N° 3 + 4 ø N° 4
As = 6.50
N° 3
N° 4 0.25 m
Pu
Kg/cm2
fy Kg/cm2
Ag
Ag cm2
Ag cm2
As cm2
Asmin
Asmin cm2
As cm2
cm2
𝑨_𝒈≥𝑷𝒖/(𝟎.𝟒𝟓(〖 ′〗𝒇 _𝒄+ 𝝆 . 𝒇_𝒚))
𝑷_𝒏=𝟎.𝟖𝟎 [𝟎.𝟖𝟓∙ 〖 ′〗𝒇 _𝒄 (𝑨_𝒈−𝑨_𝒔 )+𝒇_𝒚∙ _𝑨 𝒔 ]
𝑨_(𝒔 𝒎𝒊𝒏)=𝟎.𝟎𝟏 𝒙 𝑨_𝒈
0.25 m