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Page 1: Tanque Imhoff

Tanque Imhoff

V=V s+V d+V n

V s=P×q× t

Donde:

P=746 [hab ]

q=0.70D

D=dotaciondeagua potableen l /hd

q=0.70×130=91[ lhd ]V s=746×91×2=135772 [ l ]

V d=P×Ld

Donde:

Ld=50 [l /hd ]

V d=746×50=37300 [l ]

V n=1.20 l

V=135772+37300+1.20

V=173073.2 [ l ]

Forma : rectangular

Dimensiones:

Ancho B = 6 m Largo L = 15 m Profundidad H = 7 m

Profundidad de cámara decantación h1=1.50 [m ] h2=1.70 [m ]

Page 2: Tanque Imhoff

h3=2.60 [m ]